Find the probability that a randomlyselected point within the circle fallsin the red shaded area (square).r= 4 cm412 cm[? ]%Round to the nearest tenth of a percent.Enter

Respuesta :

Answer:

63.7%

Explanation:

To know the probability, we need to calculate the area of the circle and the area of the square.

The area of the circle is equal to:

[tex]A_c=\pi\cdot r^2[/tex]

Where r is the radius of the circle and π is approximately 3.14. So, the area of the circle is:

[tex]\begin{gathered} A_c=3.14\times4^2 \\ A_c=3.14\times16 \\ A_c=50.24 \end{gathered}[/tex]

On the other hand, the area of the square is equal to:

[tex]\begin{gathered} A_s=\text{Base}\times Height \\ A_s=4\sqrt[]{2}\times4\sqrt[]{2} \\ A_s=32 \end{gathered}[/tex]

Now, the probability that a randomly selected point within the circle falls in the square area is equal to the ratio of the areas calculated above. So, the probability is:

[tex]P=\frac{A_s}{A_c}=\frac{32}{50.24}=0.637=63.7\text{ \%}[/tex]

Therefore, the answer is 63.7%