Given:
[tex]\begin{gathered} y=-4x+3------1 \\ 2x+8y=10-----2 \end{gathered}[/tex]
Substitute y = -4x + 3 into equation 2
This gives
[tex]2x+8(-4x+3)=10[/tex]
Simplify and solve for x
[tex]\begin{gathered} 2x-32x+24=10 \\ -30x=10-24 \\ -30x=-14 \\ x=\frac{-14}{-30} \\ x=\frac{7}{15} \end{gathered}[/tex]
Substitute x = 7/15 into equation 1
This gives
[tex]y=-4(\frac{7}{15})+3[/tex]
Solve for y
[tex]\begin{gathered} y=-\frac{28}{15}+3 \\ y=\frac{-28+45}{15} \\ y=\frac{17}{15} \end{gathered}[/tex]
Therefore, there are two solution
[tex]x=\frac{7}{15},y=\frac{17}{15}[/tex]
