Answer:
The solution to the system of equation is the point which the two lines meet.
[tex]\begin{gathered} (-2,1) \\ x=-2 \\ y=1 \end{gathered}[/tex]Explanation:
Given the system of equation;
[tex]\begin{gathered} y=-2x-3 \\ y=\frac{1}{2}x+2 \end{gathered}[/tex]To plot the linear graphs, le us derive two ordered pairs on each equation;
[tex]\begin{gathered} At\text{ x = 2} \\ y=-2x-3=-2(2)-3 \\ y=-7 \\ (2,-7) \\ \\ y=\frac{1}{2}x+2 \\ y=\frac{1}{2}(2)+2 \\ y=1+2 \\ y=3 \\ (2,3) \end{gathered}[/tex][tex]\begin{gathered} at\text{ x = -2} \\ y=-2x-3=-2(-2)-3 \\ y=4-3 \\ y=1 \\ (-2,1) \\ \\ y=\frac{1}{2}x+2 \\ y=\frac{1}{2}(-2)+2 \\ y=-1+2 \\ y=1 \\ (-2,1) \end{gathered}[/tex]Graphing the points we have;
Therefore, the solution to the system of equation is the point which the two lines meet.
[tex]\begin{gathered} (-2,1) \\ x=-2 \\ y=1 \end{gathered}[/tex]
