Respuesta :

Explanation

Given the function

[tex]\begin{gathered} f(x)=6x^3-3x^2 \\ g(x)=x^2 \end{gathered}[/tex]

Therefore;

[tex]\frac{f(x)}{g(x)}=\frac{6x^3-3x^2}{x^2}=\frac{x^2(6x-3)}{x^2}=6x-3[/tex]

Answer: Option 1

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