Ben wants to draw rectangles that each have an area of 30 square inches. The length and width of each rectangle are whole numbers of inches. Part A Decide if each statement about the possible rectangles Ben could draw is true or false Choose True or False for each statement. The rectangle can have a length of 10 inches and a width of 3 inches. O True O False The rectangle can have a length of 7 inches. O True O False The rectangle can have a width of 2 inches. O True O False The rectangle can have a length of 12 inches, a width of 3 inches, and a perimeter equal to its area. O True O False The rectangle can have a width of 5 inches and a perimeter that is less than 30 inches. O True O False

Respuesta :

The area of a rectangle can be determined by the following equation:

[tex]\text{Area = Lenght }\times\text{ Width}[/tex]

First statement: The rectangle can have a length of 10 inches and a width of 3 inches (True!).

[tex]\text{Area = 10}\times3\text{ = 30 square inches}[/tex]

Second statement: The rectangle can have a length of 7 inches (False!). If the Area must be 30 square inches and the length and width of each rectangle are whole numbers of inches:

[tex]30\text{ = 7}\times\text{Width}[/tex][tex]\text{Width = 4.28}[/tex]

Width is not a whole number.

Thrid statement: The rectangle can have a width of 2 inches (True!)

[tex]30\text{ = 2}\times\text{Length}[/tex][tex]\text{Length = 15}[/tex]

Fourth statement: The rectangle can have a length of 12 inches, a width of 3 inches, and a perimeter equal to its area (False!)

[tex]\text{Area = 12}\times3\text{ = 36 }\ne30[/tex]

Fifth statement: The rectangle can have a width of 5 inches and a perimeter that is less than 30 inches (True!). Suppose that the length is 6 inches. The perimeter would be 5+5+6+6 = 22 inches and the area:

[tex]\text{Area = 5}\times6\text{ = 30 square inches}[/tex]

Therefore, the answers will be True-False-True-False-True.