Respuesta :
Given:
Equation of a circle is
[tex](x-4)^2+(y+3)^2=29[/tex]Required:
What is the center and the radius of the circle?
Explanation:
In a circle, if the coordinate of the center are (h, k), r is the radius, and (x, y) is any point on the circle., then the center of circle formula is given by
[tex](x-h)^2+(y-k)^2=r^2[/tex]Now, we have equation
[tex](x-4)^2+(y+3)^2=29[/tex][tex]\text{ In which center }(h,k)=(4,-3)\text{ and radius }\sqrt{29}.[/tex]Answer:
Hence, above is the center and radius of circle.
