Answer:
B. 16.3 m
Explanation:
Given
The velocity, u = 19 m/s
The angle of inclination, θ = 70°
The acceleration due to gravity, g = 9.8 m/s²
The maximum height is calculated below
[tex]H=\frac{u^2sin^2\theta}{2g}[/tex]
Substitute the given parameters into the formula above
[tex]\begin{gathered} H=\frac{19^2\times(sin70)^2}{2(9.8)} \\ \\ H=\frac{318.771}{19.6} \\ \\ H=16.3\text{ m} \\ \\ \end{gathered}[/tex]
The maximum height of the ball = 16.3 m
