Note that a horizontal line has a slope of 0.
From the problem, we have a line x = 4 which is a vertical line and any line that is perpendicular to a vertical line is a horizontal line.
We need to find the equation of the line perpendicular to x = 4 and contains the point
(-3, 1).
Since the line will be a horizontal line, the slope will be 0.
Using point-slope formula :
[tex]y-y_1=m(x-x_1)[/tex]where (x1, y1) is a point on the line and m is the slope.
This will be :
[tex]\begin{gathered} y-1=0(x+3) \\ y-1=0 \\ y=1 \end{gathered}[/tex]The answer is y = 1
The graph will be :
