To solve this problem we can draw or circle so:
So to find the area we need to find the hight so we can use the sin propertie so:
[tex]\sin (6)=\frac{h}{9}[/tex]and we solve for h so:
[tex]\begin{gathered} h=9\sin (6) \\ h=0.9 \end{gathered}[/tex]So the area will be:
[tex]\begin{gathered} A=\frac{6.6\cdot0.9}{2} \\ A=2.9 \end{gathered}[/tex]
