Solution (9):
Given the figure;
Using the tangent trigonometry ratio;
[tex]\begin{gathered} \tan\theta=\frac{opposite}{adjacent} \\ Where; \\ \theta=58^o,opposite=x,adjacent=15 \end{gathered}[/tex]
Thus;
[tex]\tan(58^o)=\frac{x}{15}[/tex]
Then, the equation to solve for the missing length is;
[tex]x=15\tan(58^o)[/tex]
