Two containers designed to hold water are side by side, both in the shape of acylinder. Container A has a radius of 6 feet and a height of 16 feet. Container B has aradius of 7 feet and a height of 14 feet. Container A is full of water and the water ispumped into Container B until Container A is empty.To the nearest tenth, what is the percent of Container B that is full after the pumpingis complete?playContainer AContainer B-7h.Submit AnswerAnswer:

Two containers designed to hold water are side by side both in the shape of acylinder Container A has a radius of 6 feet and a height of 16 feet Container B has class=

Respuesta :

Let's find the volume of each container

The volume of the container A is:

[tex]\begin{gathered} Va=\pi\cdot ra^2\cdot ha \\ where\colon \\ ra=6 \\ ha=16 \\ Va=\pi\cdot(6^2)\cdot16 \\ Va=576\pi ft^3 \end{gathered}[/tex]

The volume of the container B is:

[tex]\begin{gathered} Vb=\pi\cdot rb^2\cdot hb \\ where\colon \\ rb=7 \\ hb=14 \\ Vb=\pi\cdot(7^2)\cdot(14) \\ Vb=686\pi ft^3 \end{gathered}[/tex]

Let:

x = percent of container B that is full after the pumping is complete:

[tex]\begin{gathered} x\cdot Vb=Va \\ x=\frac{Va}{Vb} \\ x=\frac{576\pi}{686\pi} \\ x=0.836 \end{gathered}[/tex]

to the nearest tenth:

84.0%