Respuesta :
Given data
*The given total resistance R = 220.0 Ω
*The given peak value of the current is I_max = 1.72 A
*The given frequency is f = 60 Hz
(a)
The formula for the rms current is given as
[tex]I_{rms}=\frac{I_{\max }}{\sqrt[]{2}}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} I_{rms}=\frac{1.72}{\sqrt[]{2}} \\ =1.21\text{ A} \end{gathered}[/tex](b)
The rms voltage across the resistance is calculated as
[tex]\begin{gathered} V_{rms}=I_{rms}\times R \\ =(1.21)(220.0) \\ =266.2\text{ V} \end{gathered}[/tex](c)
The average power dissipated in the circuit is calculated as
[tex]\begin{gathered} P_{avg}=V_{rms}I_{rms}_{}_{} \\ =(266.2)(1.21) \\ =322.10\text{ W} \end{gathered}[/tex](d)
The expression for the AC current as the function of time is given as
[tex]\begin{gathered} I(t)=I_{\max }\sin (2\pi ft) \\ =1.72\sin (2\times3.14\times60.0\times t) \\ =1.72\sin (376.8t) \end{gathered}[/tex]