STEP - BY - STEP EXPLANATION
What to find?
The zeros of the given equatiion.
The graph of the given equation.
Given:
[tex]y=x^2+2x-8[/tex]
Step 1
Put y=0
[tex]x^2+2x-8=0[/tex]
Step 2
Solving by factorization method;
Replace the coefficient of x, with two numbers whose product gives -8 and whose sum gives 2.
The numbers are: 4 and -2.
[tex]x^2+4x-2x-8=0[/tex]
Step 3
Factorize;
[tex]\begin{gathered} x(x+4)-2(x+4)=0 \\ \\ (x+4)(x-2)=0 \end{gathered}[/tex]
Step 4
Determine the x- values.
x = -4 and 2
Step 5
Write the quadratic equation in vertex form.
[tex]y=(x+1)^2-9[/tex]
The vertex is (-1, -9). This implies the graph opens upward with a vertex (-1, -9).
ANSWER
