Given data:
* The depth of the fish inside the ocean is h = 12.9 m.
* The density of the ocean water is,
[tex]\rho=1025kgm^{-3}[/tex]Solution:
The pressure on the fish in terms of the depth of the fish is,
[tex]P=\rho gh[/tex]where g is the acceleration due to gravity,
Substituting the known values,
[tex]\begin{gathered} P=1025\times9.8\times12.9 \\ P=129580.5\text{ Pa} \\ P=\frac{129580.5}{101325}\text{ atm} \\ P=1.28\text{ atm} \end{gathered}[/tex]Thus, the pressure on a fish in the given case is 1.28 atm.
