Answer:
[tex]230.4\text{ MS}^{-1}[/tex]Explanation:
Here, we want to get the value of x
For the second value, we have to raise the power of the unit to the power outside the bracket
Thus, we have it that:
[tex]\begin{gathered} x\text{ = 3.6 }\times\text{ 10}^3\text{ }\times M^{-2}\text{ }\times\text{ S}^{-1}\text{ }\times\text{ 0.4}^3\text{ }\times M^3 \\ x\text{ = 230.4 }\times\text{ M}^{-2}\text{ }\times M^3\text{ }\times\text{ S}^{-1} \\ x\text{ = 230.4 }\times\text{ M}^{-2+3}\text{ }\times\text{ S}^{-1} \\ x\text{ = 230.4 MS}^{-1} \end{gathered}[/tex]