Rachael had an average score of 88 on 7 equally-weighted tests. Her teacher decided to drop the lowest test grade. Rachael's average forthe 6 remaining tests is now 91. What was Rachael's lowest test score before her teacher removed that score?

Respuesta :

Let:

x = Rachael's lowest test score

y = average score of the other tests

Rachael had an average score of 88 on 7 equally-weighted tests. so:

[tex]88=\frac{x+y}{7}[/tex]

Her teacher decided to drop the lowest test grade. Rachael's average for

the 6 remaining tests is now 91. so:

[tex]\begin{gathered} 91=\frac{y}{6} \\ so\colon \\ y=6\cdot91 \\ y=546 \end{gathered}[/tex]

Replace the valuel of y into the first equation:

[tex]88=\frac{x+546}{7}[/tex]

solve for x:

[tex]\begin{gathered} 88\cdot7=x+546 \\ 616=x+546 \\ x=616-546 \\ x=70 \end{gathered}[/tex]