The given point is (15,-19) and the slope is 3/8.
The equation of line in slope-point form is given by:
[tex]\begin{gathered} y-(-19)=\frac{3}{8}(x-15) \\ y+19=\frac{3}{8}(x-15) \\ 8y+152=3x-45 \\ 8y-3x+197=0 \end{gathered}[/tex]So the equation is given by 8y-3x+197=0.
