a car coasts 62.2 meters along a hil that makes a 28.3° angle with the ground. if the car's mass is 1234 kilograms, then what is the change in potential energy?

Respuesta :

Given,

The distance moved by car along the hill, d=62.2 m

The angle of inclination of the hill, θ=28.3°

The mass of the car, m=1234 kg

In the above diagram h is the height at which car is after moving along 62.2 m up the hill.

The height h is given by,

[tex]h=d\sin \theta[/tex]

On substituting the known values,

[tex]\begin{gathered} h=62.2\times\sin 28.3^{\circ} \\ =29.49\text{ m} \end{gathered}[/tex]

Potential energy is the energy possessed by an object due to its position.

The change in the potential energy of the car is given by,

[tex]E=\text{mgh}[/tex]

Where g is the acceleration due to gravity.

On substituting the known values,

[tex]\begin{gathered} E=1234\times9.8\times29.49 \\ =356.63\times10^3\text{ J} \\ =356.63\text{ kJ} \end{gathered}[/tex]

Thus the change in the potential energy of the car is 356.63 kJ

Ver imagen TynleighW651625