If the horizontal force of 200N is sufficient to start moving a body of mass 50Kg along awooden floor. Calculate the coefficient of friction (take gravity = 10ms-2). What typeof coefficient of friction is it?

Respuesta :

Given:

• Horizontal force, Fx = 200 N

,

• Mass of body = 50 kg

,

• Acceleration due to gravity, g = 10 m/s².

Let's find the coefficient of friction.

To find the coefficient of friction, apply the formula:

[tex]F=F_n*\mu[/tex]

Where:

f is the frictional force = 200 N

Fn is the normal force.

μ is the coefficient of friction.

To find Fn, we have:

Fn = m x g = 50 x 10 = 500 N

Thus, to find the coefficient of friction, we have:

[tex]\begin{gathered} \mu=\frac{f}{F_n} \\ \\ \mu=\frac{f}{m*g} \\ \\ \mu=\frac{200}{500} \\ \\ \mu=0.4 \end{gathered}[/tex]

Therefore, the coefficient of friction is 0.4

The type of coefficient of friction is the static friction coefficient.

ANSWER:

• Coefficient of friction = 0.4

• Static friction coefficient.