Given:
[tex]\frac{[(2i)^4]^2}{16i^5}[/tex]
Find-:
Simplify
Sol:
Simplify then:
Value of :
[tex]\begin{gathered} i=\sqrt{-1} \\ \\ i^2=-1 \\ \\ i^4=1 \end{gathered}[/tex]
So the simplification is:
[tex]\begin{gathered} =\frac{[(2i)^4]}{16i^5} \\ \\ =\frac{2^4\times i^4}{16i^4\times i} \\ \\ =\frac{16\times1}{16(1)\times i} \\ \\ =\frac{16}{16i} \\ \\ =\frac{1}{i} \end{gathered}[/tex]
Simplify the value is:
[tex]\begin{gathered} =\frac{1}{i} \\ \\ =\frac{1}{i}\times\frac{i}{i} \\ \\ =\frac{i}{i^2} \\ \\ =\frac{i}{-1} \\ \\ =-i \end{gathered}[/tex]
So simplify value is: "-i"
