Solution:
Given that;
A student earned the following grades B, A, A, C, and D with the corresponding numbers of credit hours 5, 3, 4, 3, and 2.
Total credit hours is
[tex]=5+3+4+3+2=17\text{ hours}[/tex]
To find the G.P.A of the student, the formula will be
[tex]G.P.A=\frac{5B+3A+4A+3C+2D}{17}[/tex]
The grading assigns quality points as follows
[tex]\begin{gathered} A=4 \\ B=3 \\ C=2 \\ D=1 \\ F=0 \end{gathered}[/tex]
Substituting the quality points for the variables into the formula above
[tex]\begin{gathered} G.P.A=\frac{5(3)+3(4)+4(4)+3(2)+2(1)}{17} \\ G.P.A=\frac{15+12+16+6+2}{17} \\ G.P.A=\frac{51}{17}=3 \end{gathered}[/tex]
The student's G.P.A is 3
Hence, the student makes the dean's list.
