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A 12-liter container has a pressure of 3 atmospheres.The container is sent underground, with resulting compression into 6 L.Applying Boyle's Law, what will the new pressure be?

Respuesta :

Step 1

Given;

[tex]\begin{gathered} P_1=3atm \\ v_1=12l \\ v_2=6l \\ p_2=? \end{gathered}[/tex]

Step 2

Boyle's law is given as

[tex]p_1(v_1)=p_1(v_2)[/tex][tex]\begin{gathered} 3(12)=6(p_2) \\ 36=6p_2 \\ p_2=\frac{36}{6}=6atm \end{gathered}[/tex]

Answer;

[tex]The\text{ new pressure = 6atm}[/tex]

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