Using the formula;
[tex]A=p(1+\frac{r}{n})^{nt}[/tex]From the question,
P= $1000 r =24%=0.24 n=365
t = 1/12
Substitute the values into the formula
[tex]A=1000(1+\frac{0.24}{365})^{365\times\frac{1}{12}}[/tex]So we will go ahead and evaluate
[tex]A=1000(1+0.00065753425)^{30.4166667}[/tex][tex]A=1000(1.00065753425)^{30.4166667}[/tex][tex]A\approx1020.19[/tex]The final ammount is approximately $1020.19