Solution
Step1
Add all the given fractions:
[tex]\begin{gathered} \frac{1}{3}\text{ + }\frac{1}{6}\text{ + }\frac{1}{8} \\ \\ \frac{16+8+6}{48} \\ \\ \frac{30}{48} \\ \\ \frac{15}{24} \end{gathered}[/tex]Step 2
Subtract 15/24 from 1 to find the holiday advertised are in the uk
[tex]\begin{gathered} 1\text{ - }\frac{15}{24} \\ \\ =\text{ }\frac{9}{24} \\ \\ =\frac{3}{8} \\ \end{gathered}[/tex]