Explanation
We are asked to get the equation of the circle with the centre at (2,3) and a radius of 6
To do so, we will have to use the fact that the equation defines the equation of a circle
[tex]\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ where \\ a,b=center \\ a=2,b=3 \\ r=6 \end{gathered}[/tex]So, we will substitute the above into the formula
We will have the equation as
[tex](x-2)^2+(y-3)^2=6^2[/tex]