Given :
A portion of $ 100,000 (x) was invested with a 3% after one year.
The rest of the investment (y) obtained a return of 1%.
So, the rest y = 100,000 - x
The total return = 1800
So,
3% of x + 1% of y = 1800
1) What equation shows the return on investment?
The equation will be:
[tex]\text{0}.03x+0.01y=1800\rightarrow(1)[/tex]2) What equation shows how the 100,000 were divided?
The equation will be:
[tex]x+y=100000\rightarrow(2)[/tex]Solve the previous equation to find the part (3) and (4)
so,
From the second equation: y = 100,000 - x
Substitute with x into equation (1)
So,
[tex]\text{0}.03x+0.01(100000-x)=1800[/tex]Solve the equation to find x:
[tex]\begin{gathered} 0.03x+0.01\cdot100000-0.01x=1800 \\ \text{0}.02x+1000=1800 \\ 0.02x=1800-1000 \\ \text{0}.02x=800 \\ \\ x=\frac{800}{0.02}=40000 \end{gathered}[/tex]Substitute with x into the equation (2) to find y
[tex]\begin{gathered} 40000+y=100000 \\ y=100000-40000 \\ \\ y=60000 \end{gathered}[/tex]3) how much money was invested at a 3% rate of return?
The answer will be x = $40,000
4) How much money is at a rate of return of 1%?
The answer will be y = $60,000