This is a practice question that im looking to get help with! Thank you.

we have that
x=t+2 -------> t=x-2 -----> equation A
y=t/(t+6) ------> equation B
substitute equation A in equation B
so
[tex]y=\frac{x-2}{(x-2+6)}[/tex][tex]y=\frac{x-2}{(x+4)}[/tex]therefore
the answer is