Answer:
1.65 x 10⁵ J.
Explanation:
We know that the pressure P = 1.55 x 10⁶ N/m² and the radius is r = 0.205 m.
Then, we need to calculate the volume ΔV using the following equation:
[tex]\Delta V=\pi r^2h[/tex]Where h is the distance moved by the piston. So, replacing r = 0.205 m, and h = 0.805 m, we get
[tex]\begin{gathered} \Delta V=\pi(0.205m)^2(0.805\text{ m\rparen} \\ \Delta V=0.106\text{ m}^3 \end{gathered}[/tex]Then, the work done is equal to
[tex]\begin{gathered} W=P\Delta V \\ W=(1.55\times10^6\text{ N/m}^2)(0.106\text{ m}^3) \\ W=1.65\times10^5\text{ J} \end{gathered}[/tex]Therefore, the answer is 1.65 x 10⁵ J.
