Given : a right angle triangle ABC
Angle C is the right angle
[tex]\begin{gathered} b=14 \\ c=14\sqrt[]{2} \end{gathered}[/tex][tex]\begin{gathered} \cos A=\frac{adjacent}{hypotenuse} \\ \\ \cos A=\frac{b}{c}=\frac{14}{14\sqrt[]{2}}=\frac{1}{\sqrt[]{2}} \\ \\ A=\cos ^{-1}(\frac{1}{\sqrt[]{2}})=45 \end{gathered}[/tex]