Step 1:
First, find the total number of students.
Let the total number of students = m
Step 2:
Find the total number of students using the percentage of 4 books.
48 students listed 4 books with a percentage of 16%
[tex]\begin{gathered} 48\text{ = 16\% of m} \\ 48\text{ = }\frac{16}{100}\text{ }\times\text{ m} \\ 48\text{ = }\frac{16m}{100} \\ \text{Cross multiply} \\ 16m\text{ = 48 }\times\text{ 100} \\ 16m\text{ = 4800} \\ \text{m = }\frac{4800}{16} \\ \text{m = 300} \end{gathered}[/tex]
Hence, there are 300 students.
a)
[tex]\begin{gathered} \text{Number of students that had 1 book = 24\% of 300} \\ =\text{ }\frac{24}{100}\text{ }\times\text{ 300} \\ =\text{ }\frac{7200}{100} \\ =\text{ 72 students} \end{gathered}[/tex]
72 students had 1 book.
b) What percentage more read 2 books than 4 books?
percentage that read 2 books = 36%
percentage that read 4 books = 16%
36 - 16 = 20%
There are 20% students that read 2 books than 4 books.
