Recall that the law of sines states that:
[tex]\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}\text{.}[/tex]
Therefore, for the given triangle we get that:
[tex]\frac{1.8}{\sin30^{\circ}}=\frac{1.8}{\sin B}.[/tex]
Solving the above equation for sinB we get:
[tex]\begin{gathered} \frac{\sin30^{\circ}}{1.8}=\frac{\sin B}{1.8}, \\ \sin 30^{\circ}=\sin B, \\ \sin B=\frac{1}{2}=0.5. \end{gathered}[/tex]
Answer: sin B=0.50.
