To start solving this question, we need to remember the groups of numbers:
From that draw, we can deduce that the numbers of the options:
[tex]\begin{gathered} 1)\text{ }\sqrt[]{36} \\ 4)\text{ }\sqrt[]{15} \end{gathered}[/tex]
are Irrational numbers.
and the numbers:
[tex]\begin{gathered} 2)\text{ }\frac{14}{7} \\ 3)\frac{6}{11} \end{gathered}[/tex]
are Rational numbers.
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