Given data:
* The mass of the truck is m_1 = 3000 kg.
* The mass of the parked car is m_2 = 1000 kg.
* The initial velocity of the truck is u_1 = 10 m/s.
* The initial velocity of the parked car is u_2 = 0 m/s.
* The final velocity of the car is v_2 = 15 m/s.
Solution:
According to the law of conservation of momentum, the net momentum of the system before and after the collision is the same.
Thus,
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
Substituting the known values,
[tex]\begin{gathered} 3000\times10+1000\times0=3000v_1+1000\times15 \\ 30000+0=3000v_1+15000 \\ 3000v_1=30000-15000 \\ 3000v_1=15000 \end{gathered}[/tex]
By simplifying,
[tex]\begin{gathered} v_1=\frac{15000}{3000} \\ v_1=5\text{ m/s} \end{gathered}[/tex]
Thus, the velocity of the truck is 5 meters per second.
