A pilot flies in a straight path for 1 h 30 min. She then makes a course correction, heading 10 degrees tothe right of her original course, and flies 2 h in the new direction. If she maintains a constant speed of 635mi/h, how far is she from her starting position?Your answer ismi

A pilot flies in a straight path for 1 h 30 min She then makes a course correction heading 10 degrees tothe right of her original course and flies 2 h in the ne class=

Respuesta :

Let's first make a diagram of the problem:

What we must find is the value of the line that is shown in green. For this we can first find the other two measures of the triangle, like this:

[tex]635\frac{mi}{h}\cdot1.5h=952.5\text{ mi}[/tex]

And

[tex]635\frac{mi}{h}\cdot2=1270\text{ mi}[/tex]

Since we have the measures of two of the sides and the angle opposite the one we want to find, we can use the cosine theorem:

[tex]a^2=952.5^2+1270^2-2(952.5)(1270)\cdot\cos (170_{})[/tex][tex]a=2214.22\text{ mi}[/tex]

She is 2214.22 miles far from the starting point.

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