From the function, we can conclude:
[tex]\begin{gathered} (x+6)^3 \\ x=-6_{\text{ }}Multiplicity_{\text{ }}3 \\ ---------- \\ (x-9)^2 \\ x=9_{\text{ }}Multiplicity_{\text{ }}2 \\ ----------- \\ x-6 \\ x=6_{\text{ }}Multiplicity_{\text{ }}1 \\ ----------- \\ (x+4)^3 \\ x=-4_{\text{ }}Multiplicity_{\text{ }}3 \end{gathered}[/tex]
Answer:
Zero(s) of multiplicity one: 6
Zero(s) of multiplicity two: 9
Zero(s) of multiplicity three: -6, -4
