[tex]\begin{gathered} I\text{f }h\mleft(a\mright)=3a^2-6\text{ and }g(a)\text{ = 2a-3} \\ Then,h(x)=3x^2-6\text{ , g(x) = 2x-3} \\ Therefore,g^0h\mleft(x\mright)=g\mleft(3x^2-6\mright) \\ =2(3x^2-6)\text{ - 3} \\ 6x^2-12-3 \\ 6x^2-15 \\ \end{gathered}[/tex]
