[tex]\frac{6x}{x-3}\div\frac{2x}{4x-12}[/tex][tex]\begin{gathered} \frac{6x}{x-3}\times\frac{4x-12}{2x} \\ \frac{6x}{x-3}\times\frac{4(x-3)}{2x} \\ \frac{6x(4x-12)}{2x(x-3)} \\ \frac{6(4x-12)}{x-3} \end{gathered}[/tex]
The Solution is:
[tex]x<3\text{ or x>3}[/tex]
The interval notation:
[tex](-\infty,3)\text{ U (}3,\infty)[/tex]
