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A committee must be formed with 3 teachers and 4 students. If there are 8 teachers to choose from, and 16 students, how many different ways could the committee be made?

Respuesta :

Answer:

[tex]\text{ Total number of ways=}101920[/tex]

Step-by-step explanation:

To calculate the different ways of this combination:

*3 teachers from 8 teachers

*4 students from 16 students

Then,

[tex]\frac{16!}{(16-4)!\times4!}\times\frac{8!}{(8-3)!\times3!}=Total\text{ number fo ways}[/tex]

Solve.

[tex]\begin{gathered} \text{ Total number of ways=}1820\cdot56 \\ \text{ Total number of ways=}101920 \end{gathered}[/tex]

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