First we need to isolate y of the equation given
[tex]\begin{gathered} 2x-3y=5 \\ -3y=-2x+5 \\ y=\frac{2}{3}x-\frac{5}{3} \end{gathered}[/tex]in order to be parallel lines, they have to have the same slope
The slope of the given line is 2/3
The equation will be
[tex]y+1=\frac{2}{3}(x-2)[/tex]And then we isolate the y
[tex]\begin{gathered} y=\frac{2}{3}x-\frac{2}{3}-1 \\ y=\frac{2}{3}x-\frac{7}{3} \end{gathered}[/tex]ANSWER
y=2/3 x -7/3
