We need to first graph a line that goes through the point (-14, 0).
The chosen line passes through the point (-14,0) and (0, 28).
The slope of a line is given by:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Where m is the slope, (x1,y1) is the first point and (x2,y2) is the second point. Applying these points to the problem:
[tex]m=\frac{28-0}{-0-(-14)}=\frac{28}{14}=2[/tex]
The slope of the line is 2.
The intercept of the line is the point at which it crosses the "y" axis. In this case this point is (0,28).
We can write the line in its slope-intercept form, since we already calculated those values. This form is given by:
[tex]y(x)=m\cdot x+b[/tex]
Where "m" is the slope and "b" is the intercept, therefore the equation of the line is:
[tex]y(x)=2\cdot x+28[/tex]
