a) Initial Value = 5575
Decay factor = 0.35
Explanation:The given expression is:
[tex]Y\text{ = 5575}\times(0.65)^t[/tex]a) What is the initial value
The initial value of Y will take place when t = 0
Substituting t = 0 into the given equation:
[tex]Y\text{ = 5575}\times(0.65)^0[/tex][tex]Y=\text{ 5575 }\times\text{ 1 = 5575}[/tex]The initial value is Y = 5575b) What is the decay factor
The value of a substance due to an exponential decay is given by the general expression:
[tex]Y=A(1-r)^t[/tex]Where A = original/Initial value, and r = decay rate
Comparing the above equation with the given equation shown below:
[tex]Y=5575(0.65)^t[/tex]It is clear from the comparison of both equations that A = 5575 and :
1 - r = 0.65Solving for r:r = 1 - 0.65r = 0.35The decay factor is 0.35