SOLUTION:
Starting from the red graph;
The intercept (c) = -4
Picking two points on the graph
(3,5) and (0,-4)
[tex]\begin{gathered} m\text{ = }\frac{y_2-y_1}{x_2-x_1_{}\text{ }}\text{ = }\frac{5-(-4)}{3-0}\text{ = }\frac{5+4}{3}\text{ = }\frac{9}{3}\text{ = 3} \\ \\ y\text{ = 3x - 4} \\ y\text{ }\ge\text{ 3x - 4} \end{gathered}[/tex]
From the blue graph;
The intercept (c) = 8
Picking two points on the graph
(0,3) and (1,5)
[tex]\begin{gathered} m\text{ = }\frac{y_2-y_1}{x_2-x_1\text{ }}\text{ = }\frac{8-5}{0-1}\text{ = }\frac{3}{-1}\text{ = -3} \\ \\ y\text{ = -3x + 8} \\ y<\text{ -3x + 8} \end{gathered}[/tex]
These are the systems of linear equations that are represented by the graph.
