Given the recursive formula:
[tex]a_n=\frac{2+a_{n-1}}{2}[/tex]and that the first term (that is a1=10) we have:
[tex]\begin{gathered} a_2=\frac{2+10}{2}=\frac{12}{2}=6 \\ a_3=\frac{2+6}{2}=\frac{8}{2}=4_{} \end{gathered}[/tex]Therefore the third term is 4
