Please help me with this problem so that my son can understand better. Let f(x)=−0.5(x−8)^2−2.What is the average rate of change for the quadratic function from x=−4 to x = 8? Enter your answer in the box.

Please help me with this problem so that my son can understand better Let fx05x822What is the average rate of change for the quadratic function from x4 to x 8 E class=

Respuesta :

The function is given to be:

[tex]f(x)=-0.5(x-8)^2-2[/tex]

To calculate the average rate of change between two points, we can use the formula:

[tex]\Rightarrow\frac{f(a)-f(b)}{a-b}[/tex]

where a and b are the points.

For the function provided, we are to find the rate of change between -4 and 8. Hence, our formula will be:

[tex]\frac{f(-4)-f(8)}{-4-8}=\frac{f(-4)-f(8)}{-12}[/tex]

We can evaluate f(-4) and f(8) to be:

[tex]\begin{gathered} f(-4)=-0.5(-4-8)^2-2=-0.5(-12)^2-2=-0.5(144)-2=-72-2=-74 \\ f(8)=-0.5(8-8)^2-2=-2 \end{gathered}[/tex]

Therefore, the average rate of change is calculated to be:

[tex]\Rightarrow\frac{-74-(-2)}{-12}=\frac{-74+2}{-12}=\frac{-72}{-12}=6[/tex]

The average rate of change is 6.