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A 290K gas in a 1L container is transfered to a container and its temperature decreased to 250K. What is the volume of the container it was transfered to in L?

Respuesta :

Answer = 0.86L

Given that

• T1 = 290K,

,

• T2 = 250K

,

• V1 = 1L

,

• V2=...?

We will use Charles's law formula to determine the resulting volume

V1 / T1 = V2 / T2.

→V2 = (V1*T2 )/T1

=1*250/290

=0.86 L

This is true because when temperature decreases , volume also decreases .

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