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Pat's rug is 11 3/12 ft longLamar's rug is 4 6/11 ft longAlfred's rug is 8 9/12 ft longWrite the length of each person's rug written as an improper fraction

Respuesta :

For Pat's rug, we have the following improper fraction:

[tex]11\frac{3}{12}=\frac{12(11)+3}{12}=\frac{132+3}{12}=\frac{135}{12}[/tex]

For Lamar's rug we have:

[tex]4\frac{6}{11}=\frac{4(11)+6}{11}=\frac{44+6}{11}=\frac{50}{11}[/tex]

Finally, for Alfred' rug we have:

[tex]8\frac{9}{12}=\frac{8(12)+9}{12}=\frac{96+9}{12}=\frac{105}{12}[/tex]

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