0.49moles
According to the ideal gas equation
[tex]PV=nRT[/tex]where:
• P is the ,pressure ,of the gas
,• V is the ,volume ,of the gas
,• n is the ,number of moles
,• R is the ,Gas constant
,• T is the ,temperature, (in Kelvin)
Given the following parameters at STP
[tex]\begin{gathered} P=1atm \\ V=11.0L \\ R=0.08205Lat\text{m/molK} \\ T=273K \end{gathered}[/tex]Determine the required number of moles
[tex]\begin{gathered} n=\frac{PV}{RT} \\ n=\frac{1atm\times11.0L}{0.08205\times273} \\ n=\frac{11}{22.399} \\ n=0.49moles \end{gathered}[/tex]Hence the number of moles present in 11.0L of neon gas at STP at 0.49moles
