The blue line passes through (0,6) and (-2,8). The equation of blue line can be determined as,
[tex]\begin{gathered} \frac{y-6}{x-0}=\frac{8-6}{-2-0} \\ \frac{y-6}{x}=\frac{2}{-2} \\ y-6=-1(x) \\ y=-x+6 \end{gathered}[/tex]The red line passes through (-2,8) and (-3,7). The equation of red line can be determined as,
[tex]\begin{gathered} \frac{y-8}{x-(-2)}=\frac{8-7}{-2-(-3)} \\ \frac{y-8}{x+2}=\frac{1}{1} \\ y-8=x+2 \\ y=x+10 \end{gathered}[/tex]Thus, the required system of equations is,
y=-x+6 and y=x+10.
