ok
length of side 1 = 6
short leg = 4
Pythagorean theorem
[tex]\begin{gathered} PQ\text{ = }\sqrt[]{(6)^2+(4)^2} \\ PQ\text{ = }\sqrt[]{36\text{ + 16}} \\ PQ\text{ = }\sqrt[]{52} \end{gathered}[/tex]Using the distance formula
[tex]\begin{gathered} PQ\text{ = }\sqrt[]{(7-1)^2+(2-6)^2} \\ PQ\text{ = }\sqrt[]{6^2+4^2} \\ PQ\text{ = }\sqrt[]{36\text{ + 16}} \\ PQ\text{ = }\sqrt[]{52} \end{gathered}[/tex]