Given the following formula in getting the velocity of an object:
[tex]\text{ v = }\sqrt{64\text{h}}[/tex]
Where,
h = height the object has fallen
We get,
[tex]\text{ v = }\sqrt{64h}\text{ = }\sqrt{64\text{ x 25}}[/tex][tex]\text{ v = }\sqrt{1,600}[/tex][tex]\text{ v = 40 ft./sec.}[/tex]
Therefore, the velocity of the object falling at 25 ft, is 40 ft./sec.
